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9x^2-59x+20=0
a = 9; b = -59; c = +20;
Δ = b2-4ac
Δ = -592-4·9·20
Δ = 2761
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-59)-\sqrt{2761}}{2*9}=\frac{59-\sqrt{2761}}{18} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-59)+\sqrt{2761}}{2*9}=\frac{59+\sqrt{2761}}{18} $
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